[A,[B,C]]+[B,[C,A]]+[C,[A,B]]=[A,BC−CB]+[B,CA−AC]+[C,AB−BA]=A(BC−CB)−(BC−CB)A+B(CA−AC)−(CA−AC)B+C(AB−BA)−(AB−BA)C=ABC−ACB−BCA+CBA+BCA−BAC−CAB+ACB+CAB−CBA−ABC+BAC=0By the commutator’s definitionExpanding the multiplicationsCancelling the repeated terms